0=5-9.6t^2

Solution for 0=5-9.6t^2 equation:

0=5-9.6t^2

We move all terms to the left:

0-(5-9.6t^2)=0

We add all the numbers together, and all the variables

-(5-9.6t^2)=0

We get rid of parentheses

9.6t^2-5=0

a = 9.6; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·9.6·(-5)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*9.6}=\frac{0-8\sqrt{3}}{19.2}
=-\frac{8\sqrt{3}}{19.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*9.6}=\frac{0+8\sqrt{3}}{19.2}
=\frac{8\sqrt{3}}{19.2}
$